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Simple Interest

Learning Goals

By the end of this chapter, you will be able to:


The Hook: The ₹10,000 Lesson

Two friends each borrow ₹10,000 for 3 years at 10% per year. One borrows on simple interest, the other on compound interest. At the end, the first friend pays back ₹13,000. The second pays back ₹13,310. Same money, same rate, same time — yet ₹310 apart.

That ₹310 gap is exactly why examiners love this chapter. Simple Interest looks trivially easy, and that is precisely the trap: under exam pressure, students mix up SI and CI, forget to convert months into years, or misread "amount" as "interest." Master SI deeply, and you not only secure these marks — you build the foundation for Compound Interest, which is just SI applied repeatedly.


1. What Simple Interest Really Means

When you borrow money, you pay a "rent" for using it. That rent is called interest. In simple interest, the rent is calculated only on the original sum (the principal), every single year. It never grows, never compounds.

The core formula:

SI = (P × R × T) / 100

Amount A = P + SI = P(1 + RT/100)

🧠 Active Recall: Without looking — if P = ₹5,000, R = 8%, T = 2 years, what is the SI? What is the Amount? (SI = ₹800, A = ₹5,800. Check yourself.)


2. Why the Formula Works (Don't Just Memorise It)

R% means: every year, you pay ₹R for every ₹100 of principal. So in one year, interest on ₹P is (P × R)/100. Over T years, multiply by T. That's it — the whole formula is just "rent per year × number of years."

This understanding unlocks the rearrangements instantly:

Notice the pattern: whatever you want sits alone; SI × 100 is always on top; the other two variables multiply below.

🧠 Active Recall: A sum earns ₹1,200 as SI in 4 years at 5%. Can you find the principal using the rearranged formula? (P = 1200 × 100 / (5 × 4) = ₹6,000.)


3. The Time Trap: Months and Days

Examiners rarely give clean years. Convert carefully:

Example: SI on ₹7,300 at 6% for 73 days.
T = 73/365 = 1/5 year. SI = (7300 × 6 × 1/5)/100 = ₹87.60.

A classic trap: "2 years 6 months" must become 2.5 years before you apply the formula — students who plug in 2.6 lose the mark.


4. The "Becomes n Times" Family

This is the most repeated advanced pattern. If a sum becomes n times itself (i.e., Amount = nP), then the interest earned is (n − 1)P.

So: (n − 1)P = PRT/100 → RT = 100(n − 1)

Example: A sum doubles in 8 years at SI. Find the rate.
Here n = 2, so RT = 100 → R × 8 = 100 → R = 12.5%.

The killer follow-up: "A sum doubles in 8 years. In how many years will it become 4 times (at the same SI rate)?"
Doubling means earning 1P of interest in 8 years. To become 4 times, you must earn 3P — three times the interest — so 3 × 8 = 24 years. In SI, interest grows linearly, so time scales linearly. (In CI it would be 16 years — a favourite confusion trap!)

🧠 Active Recall: A sum triples in 12 years at simple interest. When will it become 5 times? (Tripling = earning 2P in 12 years, so 1P per 6 years. Five times = earning 4P → 24 years.)


5. Split Investments and Rate Changes

Split investment: ₹P is split into two parts at rates R₁ and R₂ for the same time, earning equal interest. Then the parts are in the ratio R₂ : R₁ (inverse ratio — the higher rate needs the smaller part).

Example: ₹10,000 split at 6% and 8% for equal SI in the same time. Parts ratio = 8 : 6 = 4 : 3, so the part at 6% is 4/7 × 10,000 = ₹5,714.29 and the part at 8% is 3/7 × 10,000 = ₹4,285.71. Verify: SI₁ = (5714.29 × 6 × T)/100 = 342.86T and SI₂ = (4285.71 × 8 × T)/100 = 342.86T — equal. ✓

Rate change over time: If the rate is R₁ for T₁ years and R₂ for T₂ years, just add the interests:
SI = P(R₁T₁ + R₂T₂)/100


6. Instalments — The Advanced Favourite

A debt is repaid in equal annual instalments of ₹x under simple interest at rate R. The reliable method: each instalment, paid after a different number of years, clears a different slice of the loan. An instalment of ₹x paid after T years clears a principal slice of:

Principal slice = x / (1 + RT/100)

because that slice, plus T years of simple interest on it, grows to exactly ₹x. Add the slices of all instalments to get the loan:

Loan = Σ x / (1 + RTᵢ/100), where Tᵢ = 1, 2, 3, … years for the 1st, 2nd, 3rd, … instalment.

Example: A loan is repaid in 2 annual instalments of ₹1,050 each at 10% SI. Find the loan.

Lesson: there is no safe one-line shortcut here — divide each instalment by (1 + RT/100) with its own T, then add. Trust the method, not a formula you half-remember.

🧠 Active Recall: Why does each instalment get divided by a *different* factor? (Because each is paid after a different number of years, so each carries a different amount of interest.)


7. SI vs CI — Know the Boundary

For 1 year, SI and CI are identical. They diverge from year 2 onward, because CI pays interest on interest. For 2 years, the difference is P(R/100)². If a question mentions "interest on interest" or "compounded," leave this chapter's formulas behind. If the question says nothing about the type of interest, read it twice before assuming — many exams state "simple interest" explicitly, and when they don't, the wording usually tells you which one is meant.


🧠 Mnemonic: "PeRT-100"

Remember the formula as a person: Mr. PeRT works for 100.
P × R × T over 100 — Principal, Rate, Time, divided by 100. And his wife "A = P + SI" — the Amount is always Principal *plus* his salary (SI), never minus. If you can picture Mr. PeRT handing his paycheque to Mrs. A, you will never swap Amount and Interest again.


Summary Table

ConceptFormula / RuleWatch Out For
Simple InterestSI = PRT/100T must be in years
AmountA = P + SI = P(1 + RT/100)Amount ≠ Interest
Find P, R, TSI×100 on top, other two belowUnits of R (% p.a.)
Months/Days÷12 or ÷3652 yr 6 mo = 2.5, not 2.6
Becomes n timesRT = 100(n − 1)"n times" ≠ "n times more" loosely used — read carefully
Time to multiply furtherSI grows linearly with timeDon't apply CI logic
Equal SI, split sumParts in inverse ratio of ratesR₂ : R₁, not R₁ : R₂
Changing ratesSI = P(R₁T₁ + R₂T₂)/100Add interests separately
InstalmentsLoan = Σ x/(1 + RTᵢ/100)Each instalment has its own T
SI vs CISame for 1 year; differ afterDifference for 2 yrs = P(R/100)²

📌 Review this chapter after 2 days. Redo the "becomes n times" and instalment examples with a pen, without looking at the solutions — those two families decide most SI questions in Tier-II and PO Mains.

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