Trigonometry
Outline & Learning Goals
By the end of this chapter, you will be able to:
- Define all six trigonometric ratios and move fluently between them.
- Use standard angle values (0°, 30°, 45°, 60°, 90°) without hesitation.
- Apply the three fundamental identities to simplify and prove expressions.
- Handle complementary angles, compound angles, and multiple-angle formulas.
- Solve heights-and-distances problems — the single most exam-favourite application.
- Find maximum/minimum values of expressions like a·sin θ + b·cos θ — a classic Advanced-level trap zone.
The Hook: Measuring the Unmeasurable
In 1856, surveyors of the Great Trigonometrical Survey of India stood hundreds of kilometres away from a distant Himalayan peak. They never climbed it. They never touched it. Using only angles measured from the ground and the mathematics you are about to learn, they calculated its height — and declared it the tallest mountain on Earth. We now call it Mount Everest.
That is the power of trigonometry: it converts angles into distances. No ladder, no rope, no rocket — just a triangle and a few ratios. And that is exactly why examiners love it. One small formula, endless disguises.
"But Trigonometry Feels Like Memorising a Phone Directory…"
If that's you, you're not alone. Most aspirants struggle with trigonometry for one reason: they try to memorise it instead of seeing it. Every formula in this chapter is just a sentence about a right-angled triangle, translated into symbols. Once you see the triangle, the formula writes itself.
So let's rebuild trigonometry from one picture — a right-angled triangle with angle θ.
Chunk 1: The Six Ratios — One Triangle, Six Stories
In a right-angled triangle, for angle θ:
- Perpendicular (P) = side opposite to θ
- Base (B) = side adjacent to θ
- Hypotenuse (H) = side opposite the right angle (always the longest)
The six ratios:
| Ratio | Definition | Reciprocal of |
|---|---|---|
| sin θ | P / H | cosec θ |
| cos θ | B / H | sec θ |
| tan θ | P / B | cot θ |
Only three are fundamental. The other three (cosec, sec, cot) are just reciprocals. If you know sin, cos, tan — you know everything.
🧠 Active Recall: Close the book. Write the definitions of sin θ, cos θ, tan θ from memory. Now write sec θ in terms of cos θ. Check yourself.
Chunk 2: The Standard Angle Table — Derive, Don't Memorise
The famous table (0°, 30°, 45°, 60°, 90°) terrifies students. Here's the secret: you only need to memorise the sin row.
The Trick — "Square Root Ladder":
Write 0, 1, 2, 3, 4 under the five angles. Divide each by 4. Take the square root. Done.
- sin 0° = √(0/4) = 0
- sin 30° = √(1/4) = 1/2
- sin 45° = √(2/4) = 1/√2
- sin 60° = √(3/4) = √3/2
- sin 90° = √(4/4) = 1
Now:
- cos row = sin row written in reverse order.
- tan row = sin ÷ cos.
Three rows from one ladder. That's it.
🧠 Active Recall: Using the ladder, find sin 60°, cos 30°, and tan 45°. Notice anything about the first two?
Chunk 3: The Three Identities — The Constitution of Trigonometry
Everything in advanced trigonometry rests on one fact: Pythagoras' theorem, P² + B² = H². Divide this equation by H², B², and P² respectively, and you get the three fundamental identities:
- sin²θ + cos²θ = 1
- 1 + tan²θ = sec²θ
- 1 + cot²θ = cosec²θ
Mnemonic — "Some Children Take Sweets":
- Sin² + Cos² = 1 (the parent identity)
- Tan goes with Sec (T–S pair)
- Cot goes with Cosec (the remaining pair)
Advanced application: Examiners rarely ask these directly. They hide them. Example: simplify (sin θ)/(1 + cos θ) + (1 + cos θ)/(sin θ). Take the LCM — the numerator becomes sin²θ + (1 + cos θ)² = sin²θ + 1 + 2cos θ + cos²θ = 2 + 2cos θ = 2(1 + cos θ). The answer collapses to 2/sin θ = 2 cosec θ. The identity did all the work.
🧠 Active Recall: From identity 1, derive identity 2 by dividing by cos²θ. Do it on paper now.
Chunk 4: Complementary Angles — The 90° Shortcut
When two angles add to 90°, their ratios swap partners:
- sin(90° − θ) = cos θ
- tan(90° − θ) = cot θ
- sec(90° − θ) = cosec θ
Memory hook: "Co" means "complement." Sine's complement is cosine. Tangent's is cotangent. Secant's is cosecant.
Classic exam pattern: "If sin 3A = cos(A − 26°), find A." Since sin x = cos(90° − x), we get 3A + (A − 26°) = 90°, so 4A = 116°, A = 29°. One identity, ten seconds.
🧠 Active Recall: What is tan 1° · tan 2° · tan 3° … tan 89°? (Hint: pair tan 1° with tan 89° = cot 1°.)
Chunk 5: Compound & Multiple Angles — The Advanced Arsenal
These formulas power the toughest questions in SSC CGL Tier-II and IBPS PO Mains:
Compound angles:
- sin(A + B) = sin A cos B + cos A sin B
- cos(A + B) = cos A cos B − sin A sin B
- tan(A + B) = (tan A + tan B) / (1 − tan A tan B)
Double angles (put B = A above):
- sin 2A = 2 sin A cos A
- cos 2A = cos²A − sin²A = 2cos²A − 1 = 1 − 2sin²A
- tan 2A = 2 tan A / (1 − tan²A)
The examiner's favourite — the max-min rule:
For any expression a sin θ + b cos θ, the value always lies between −√(a² + b²) and +√(a² + b²).
Example: maximum value of 3 sin θ + 4 cos θ? Answer: √(9 + 16) = 5. (Recognise the 3-4-5 triangle? That's no coincidence.)
🧠 Active Recall: What is the minimum value of 5 sin θ + 12 cos θ? And what is sin 2A when sin A = 3/5, cos A = 4/5?
Chunk 6: Heights & Distances — Where Trigonometry Earns Its Salary
This is the most frequently tested application. The whole game is three steps:
- Draw the picture. Observer, object, ground — a right triangle is always hiding there.
- Identify the angle. Angle of elevation (looking up) or depression (looking down — equal to the elevation from the other side, by alternate angles).
- Pick the ratio. Almost always tan θ = height / distance, because height and ground distance are the two sides you deal with.
The two golden values:
- tan 45° = 1 → height = distance
- tan 30° = 1/√3 and tan 60° = √3 → these two angles appear in the majority of problems, often in the same question (a tower viewed from two points).
Classic pattern: From a point, the angle of elevation of a tower's top is 30°. Walking 20 m closer, it becomes 60°. Height? Set up h = d·tan 60° and h = (d + 20)·tan 30°. Solving gives h = 10√3 m. Learn this template — it repeats endlessly.
🧠 Active Recall: The shadow of a pole equals its height. What is the sun's angle of elevation? (No calculator needed.)
Chunk 7: Signs in the Four Quadrants (Advanced Extension)
For angles beyond 90°, use the unit circle. The sign rule:
"All Silver Tea Cups" (or "Add Sugar To Coffee") — going anticlockwise from the first quadrant:
| Quadrant | Positive ratios |
|---|---|
| I (0°–90°) | All |
| II (90°–180°) | Sin (and cosec) |
| III (180°–270°) | Tan (and cot) |
| IV (270°–360°) | Cos (and sec) |
So sin 150° = sin(180° − 30°) = +sin 30° = 1/2, but cos 150° = −√3/2.
🧠 Active Recall: Is tan 225° positive or negative? What is its value?
Summary Table
| Concept | Core Result | Exam Use |
|---|---|---|
| Six ratios | sin = P/H, cos = B/H, tan = P/B; rest are reciprocals | Foundation of everything |
| Standard angles | Square-root ladder: √(0/4)…√(4/4) | Direct value questions |
| Identities | sin²+cos²=1; 1+tan²=sec²; 1+cot²=cosec² | Simplification, proofs |
| Complementary | sin(90°−θ) = cos θ | Equation-solving traps |
| Double angle | sin 2A = 2 sin A cos A | Tier-II / Mains level |
| Max–Min | a sin θ + b cos θ ∈ [−√(a²+b²), +√(a²+b²)] | One-line answers |
| Heights & Distances | tan θ = height / distance | The most repeated application |
| Quadrants | All Silver Tea Cups | Angles beyond 90° |
🔁 Review This After 2 Days
Don't re-read passively. Instead, take a blank page and reconstruct from memory: (1) the standard angle table using the ladder, (2) the three identities, (3) the max-min rule, and (4) one heights-and-distances template. Whatever you can't reproduce — that's your revision list. Trigonometry is not memorised; it is rebuilt, and every rebuild makes it faster.