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Number System (Advanced)

Learning Goals

By the end of this chapter, you will be able to:


The Hook: A Number That Broke a Computer

In 1996, the European Space Agency's Ariane 5 rocket exploded less than a minute after launch. The cause? A number. A 64-bit floating-point value was squeezed into a 16-bit integer — the number was too big for its "box," the system overflowed, and a rocket worth hundreds of millions of dollars turned into fireworks.

Numbers are not just symbols. They live in *systems*, and every system has rules. In your exam, the "explosion" is quieter — one wrong assumption about remainders or unit digits, and 2 marks vanish. This chapter teaches you the rules of the box, so your numbers never overflow.


1. The Family Tree of Numbers

Let's be honest — most aspirants *think* they know number types, then lose marks on a statement like "Every integer is a rational number." (It is true, by the way.) So let's build the tree properly.

Key exam facts:

🧠 Active Recall: Close the book. Is 0.999… (repeating forever) rational or irrational? Why? *(Hint: it equals exactly 1.)*


2. Prime Numbers and Factorisation — The Atoms of Arithmetic

A prime number has exactly two factors: 1 and itself. 2 is the only even prime. 1 is *neither* prime nor composite — examiners love this.

Primes up to 100 (25 of them): 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

Fundamental Theorem of Arithmetic: Every integer greater than 1 can be written as a product of primes in exactly one way (order aside). Example: 360 = 2³ × 3² × 5.

From prime factorisation N = aᵖ × bᑫ × cʳ …:

🧠 Active Recall: How many factors does 360 have? Compute it before reading on. *(Answer: (3+1)(2+1)(1+1) = 24.)*


3. Divisibility Rules — Your Speed Weapons

DivisorRule
2Last digit even
3Sum of digits divisible by 3
4Last two digits divisible by 4
5Last digit 0 or 5
6Divisible by both 2 and 3
7Double the last digit, subtract from the rest; result divisible by 7
8Last three digits divisible by 8
9Sum of digits divisible by 9
11(Sum of digits in odd places) − (sum in even places) is 0 or a multiple of 11
12Divisible by both 3 and 4
25Last two digits 00, 25, 50, or 75

Composite divisors: To test divisibility by 72, test 8 and 9 (co-prime pair), *not* 6 and 12 — because 6 and 12 share factors. Always split into co-prime factors.

🧠 Active Recall: Is 4,95,432 divisible by 11? By 8? Do it mentally.


4. LCM and HCF — The Twin Pillars

Golden relation (for two numbers): LCM × HCF = Product of the two numbers. ⚠️ This works only for *two* numbers — a favourite trap.

Fractions:

Remainder-flavoured models (asked constantly):

🧠 Active Recall: Why does the last formula *subtract* k? Say the reason aloud in one sentence.


5. Remainders — Where Toppers Are Made

Division algorithm: Dividend = Divisor × Quotient + Remainder, with 0 ≤ Remainder < Divisor.

Negative remainders: When 47 is divided by 8, remainder is 7. But thinking of it as "−1" (since 47 = 8×6 − 1) often makes calculations faster. Negative remainder = actual remainder − divisor.

Powerful remainder facts:

Classic results:

Example: Remainder when 2¹⁰⁰ is divided by 7? Powers of 2 mod 7 cycle: 2, 4, 1 (cycle length 3). 100 = 3×33 + 1, so remainder = 2.

🧠 Active Recall: Find the remainder when 3⁵⁰ is divided by 7 using Fermat's theorem. *(3⁶ ≡ 1, so 3⁴⁸ ≡ 1, 3⁵⁰ ≡ 9 ≡ 2.)*


6. Unit Digits and Cyclicity

The unit digit of aⁿ depends only on the unit digit of a, and it cycles:

Unit digit of aCycleLength
0, 1, 5, 6same always1
22, 4, 8, 64
33, 9, 7, 14
44, 62
77, 9, 3, 14
88, 4, 2, 64
99, 12

Method: divide the exponent by the cycle length; use the remainder (if remainder is 0, use the last position of the cycle).

Example: Unit digit of 7⁹⁵? Cycle of 7 is 7, 9, 3, 1. 95 ÷ 4 leaves remainder 3 → third position → 3.

🧠 Active Recall: Unit digit of 2²⁰²⁴? *(2024 ÷ 4 remainder 0 → 4th position → 6.)*


7. Factorials — Trailing Zeros and Highest Powers

n! = 1 × 2 × 3 × … × n.

Trailing zeros in n! = number of times 5 divides n! (2s are always plentiful):

Zeros = ⌊n/5⌋ + ⌊n/25⌋ + ⌊n/125⌋ + …

Example: Zeros in 100! = 20 + 4 = 24.

Highest power of a prime p dividing n! = ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + …

For a *composite* divisor (say, highest power of 6 = 2×3 in n!), find the powers of each prime and take the limiting one.

🧠 Active Recall: How many trailing zeros does 250! have? *(50 + 10 + 2 = 62.)*


8. Base Systems — Thinking Like a Computer

We count in base 10. Computers use base 2 (binary), base 8 (octal), base 16 (hexadecimal: digits 0–9, A–F).

Base b → decimal: multiply each digit by b raised to its position (from right, starting at 0).

(1011)₂ = 1×2³ + 0×2² + 1×2¹ + 1×2⁰ = 8 + 0 + 2 + 1 = 11.

Decimal → base b: divide repeatedly by b, collect remainders bottom-to-top.

Binary ↔ Octal/Hex shortcut: group binary digits in 3s (octal) or 4s (hex) from the right.

(101101)₂ → groups 101 | 101 → (55)₈.

🧠 Active Recall: Convert (45)₁₀ to binary. *(101101)*


9. The Mnemonic Corner 🪄

"2-4-8-6, the Even Fix" — the cycle of 2 is all even digits in order: 2, 4, 8, 6. And 8's cycle is the *reverse*: 8, 4, 2, 6. Remember: "2 climbs up, 8 climbs down."

For divisibility by 11: "Odd minus Even, Zero or Eleven" — alternate digit sums must differ by 0 or a multiple of 11.


10. Examiner's Traps — Read Before You Regret

  1. "Every whole number is a natural number" — FALSE (0 is whole, not natural).
  2. "Product of two irrationals is always irrational" — FALSE (√2 × √8 = 4).
  3. LCM × HCF = product — only for *two* numbers.
  4. Remainder must be less than the divisor — options often include a value equal to the divisor.
  5. In "leaves remainder r" problems, check whether the question asks for the *smallest* or *greatest* such number.
  6. Cyclicity: when the exponent divides exactly (remainder 0), take the last element of the cycle, not the first.

Summary Table

ConceptCore Result
Factors of N = aᵖbᑫcʳ(p+1)(q+1)(r+1)
LCM × HCF= product (two numbers only)
Same remainder r on dividing a, b, cHCF of (a−r, b−r, c−r)
Smallest number leaving remainder r with divisors a, b, cLCM(a,b,c) + r
Unit digit of aⁿReduce n mod cycle length (0 → last position)
Trailing zeros in n!⌊n/5⌋ + ⌊n/25⌋ + ⌊n/125⌋ + …
Highest power of prime p in n!⌊n/p⌋ + ⌊n/p²⌋ + …
Fermat's Little Theoremaᵖ⁻¹ ≡ 1 (mod p), p prime, p ∤ a
Divisibility by 11Alternate-sum difference = 0 or multiple of 11
Binary → decimalΣ digit × 2^position

🔁 Review This After 2 Days

Don't just re-read. Cover the summary table and answer aloud:

  1. How many factors does 720 have?
  2. Remainder when 7⁸⁴ is divided by 5?
  3. Trailing zeros in 200!?
  4. Convert (110101)₂ to decimal.
  5. Smallest number which when divided by 4, 5, 6 leaves remainder 3 each time?

If any answer takes more than 30 seconds, revisit that section — then test yourself again after another 2 days. Spaced repetition is how this chapter moves from "studied" to "scored."

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